Question

1/a^2+ab + 1/ab+b^2​

Answer 1

$\frac{1}{a^{2}+ab }+\frac{1}{ab+b^{2} }=\frac{1}{a(a+b)}+\frac{1}{b(a+b)}=\frac{b+a}{ab(a+b)}=\frac{1}{ab}$