Question

Нужны все задания, кто что сможет

Answer 1

$A1)\; \; 4a+3b=0\; \; \to \; \; 4a=-3b\; ,\; \; a=-\frac{3b}{4}=-0,75b\\\\\frac{3a+5b}{5a+7b}=\frac{3\cdot (-0,75b)+5b}{5\cdot (-0,75b)+7b}=\frac{2,75b}{3,25b}=\frac{11/4}{14/4}=\frac{11}{13}\\\\Otvet:\; \; \#5\; .\\\\\\A2)\; \; y=3^{x}\; \; ,\; \; y=|x-4|\\\\x=1:\; \; y(1)=3^1=3\; \; ;\; \; \; y(1)=|1-4|=|-3|=3\; \; \Rightarrow \\\\tochka\; pereseceniya\; \; (1,3)\; .\\\\(x-x_0)^2+(y-y_0)^2=r^2\; \; \; ,\; \; r=\frac{1}{2}\\\\(x-1)^2+(y-3)^2=\frac{1}{4}\\\\Otvet:\; \; \#4\; .$

$A3)\; \; y=\frac{\sqrt{12-x^2-x}}{\sqrt{x+3}}\\\\OOF:\; \; \left \{ {{12-x^2-x\geq 0} \atop {x+3>0}} \right.\; \; \left \{ {{x^2+x-12\leq 0} \atop {x>-3}} \right. \; \; \left \{ {{(x+4)(x-3)\leq 0} \atop {x>-3}} \right.\; \; \left \{ {{x\in [-4,3\, ]} \atop {x\in (-3,+\infty )}} \right. \; \Rightarrow \\\\x\in (-3\, ,3\, ]\\\\Otvet:\; \; \#3\; .$