Question

решите плиз много баллов дам​

Answer 1

$3)(\frac{2a}{1+a}-\frac{1}{a}):\frac{a}{1+a}=\frac{2a^{2}-1-a }{a(1+a)}*\frac{1+a}{a}=\frac{2a^{2}-a-1 }{a^{2} } \\\\4)(\frac{3}{b}+\frac{b}{b-1}):\frac{b}{b-1}=\frac{3b-3+b^{2} }{b(b-1)}*\frac{b-1}{b}=\frac{b^{2}+3b-3 }{b^{2} }$

$1)\frac{b^{2} }{2b-a}*(2-\frac{a}{b})=\frac{b^{2}}{2b-a}*\frac{2b-a}{b}=b\\\\2)\frac{d^{3} }{c-3d}*(\frac{c}{d}-3)=\frac{d^{3} }{c-3d}*\frac{c-3d}{d}=d^{2}$

$3)\frac{5+3x}{x^{5}}:(\frac{3}{5}+\frac{1}{x})=\frac{5+3x}{x^{5}}:\frac{3x+5}{5x}=\frac{5+3x}{x^{5}}*\frac{5x}{3x+5}=\frac{5}{x^{4}}\\\\4)\frac{3+2y}{y^{4}}:(\frac{2}{3}+\frac{1}{y})=\frac{3+2y}{y^{4}}:\frac{2y+3}{3y}=\frac{3+2y}{y^{4}}*\frac{3y}{2y+3}=\frac{3}{y^{3}}$