Question

Помогите решить...................

Answer 1

${2}^{ ({ log_{2}3 )}^{2} } - {3}^{ log_{2}(3) } - {9}^{ log_{3}(2) } = {2}^{ ({ log_{2}3 )}^{2} } - { ({2}^{ log_{2}3 } )}^{ log_{2}3 } - {3}^{2 log_{3}(2) } = \\ \\ = {2}^{ ({ log_{2}3 )}^{2} } - {2}^{ ({ log_{2}3 )}^{2} } - {3}^{ log_{3}(4) } = - {3}^{ log_{3}(4) } = - 4$

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${a}^{ log_{a}b } = b \\ \\ n \times log_{a}b = log_{a}( {b}^{n} )$

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ОТВЕТ: - 4