Question

решите неравенство 0,3^ х^2+6≥(0,3)^х

Answer 1

$0,3^{x^2+6}=0,3^{x}\\\\x^2+6=x\\\\x^2-x+6=0\\\\\underline {x_1=-2\; ,\; x_2=3}\; \; (teorema\; Vieta)$