Question

решите Систему уравнений ​

Answer 1

{x-3y=4,

{xy-6y=1;

{x=4+3y,

{(4+3y)y-6y=1;

4y+3y^2-6y=1

3y^2-2y-1=0

D=b^2-4ac=4-4×3×(-1)=16.

y1=-b-√D/2a =2-4/6=-1/3

y2=-b+√D/2a =2+4/6=1

x1=4+3y=4+3(-1/3)=3

x2=4+3y=4+3×1=7

Ответ:

1) (3;-1/3)

2) (7;1)

Answer 2

x=4+3y

y(3y+4)-6y=1

x=4+3y

3y²+4y-6y-1=0

x=3y+4

3y²-2y-1=0

D=4+12=16

y1= (2+4)/6= 1

y2= (2-4)/6= -1/3

x1= 7

x2= 3

Ответ: (7;1), (3; -1/3)