Question

решите систему уравнений​

Answer 1

$\begin{cases}x+2y=5\\4^{x-2y}=0,25\end{cases}\Rightarrow\begin{cases}x=5-2y\\4^{5-2y-2y}=0,25\end{cases}\\\\4^{5-4y}=\frac14\\4^{5-4y}=4^{-1}\\5-4y=-1\\4y=6\\y=1,5\\\begin{cases}x=2\\y=1,5\end{cases}$