Question

Log4 8+log4 4-log4 16

Answer 1

$\log_48+\log_44-\log_416=\log_4(8\cdot4)-\log_416=\log_432-\log_416=\\ \\ =\log_4\frac{32}{16}=\log_42=\log_{2^2}2=\frac{1}{2}\log_22=\frac{1}{2}$