Предмет: Математика, автор: Aleynaakalirova

Найдите log5 iz 98 ?
Lg2=a
Lg7=b

Ответы

Автор ответа: Аноним
1

\displaystyle \log_598=\frac{\lg98}{\lg5}=\frac{\lg(2\cdot49)}{\lg5}=\frac{\lg2+\lg\overbrace{49}^{7^2}}{\lg5}=\frac{\lg2+2\lg7}{\lg5}=\dfrac{a+2b}{\lg5}

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