Question

(у-8)(2у-1)-(3у+1((5у-2)=

Answer 1

$(y - 8)(2y - 1) - (3y + 1(5y - 2)) = \\ = 2y {}^{2} - y - 16y + 8 - (15y {}^{2} - 6y + 5y - 2) = \\ = 2y {}^{2} - 17y + 8 - 15y { }^{2} + 6y - 5y + 2 = \\ = - 13y {}^{2} - 16y + 10$

Answer 2

2y²-у-16у+8-15у²+6у-5у+2=(-13у²)-16у+10