Question

Разложите на множители:
M3 n6+27;
2ay-4x+x-0,5ay;
-2ab2 +4abc-2ac2

Answer 1

1) n⁶ + 27 = (n²)³ + 3³ = (n² + 3)(n⁴ - 3n² + 9)

2) 2ay - 4x + x - 0,5ay = 1,5ay - 3x = 1,5(ay - 2x)

3) - 2ab² + 4abc - 2ac² = - 2a(b² - 2bc + c² ) = - 2a(b - c)²