Question

помогите решить задание​

Answer 1

$\int\limits^{\frac{\pi}{2}}_{\frac{\pi}{3}} {\sin x} \, dx =-\cos x |^{\frac{\pi}{2}}_{\frac{\pi}{3}}=-\cos\left(\dfrac{\pi}{2}\right)-\left(-\cos \left(\dfrac{\pi}{3}\right)\right)=0+\dfrac{1}{2}=0.5 \\ \\ \log_216=\log_22^4=4 \\ \\ |\overline{a}|=\sqrt{3^2+3^2+(-3)^2}=\sqrt{27}=3\sqrt{3} \\ \\ V=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi\cdot6^3=288\pi \ cm^3$

Answer 2

$1)\int\limits^\frac{\pi }{2} _\frac{\pi }{3}{Sinx} \, dx =-Cosx|^{\frac{\pi }{2}}_{\frac{\pi }{3} }=-Cos\frac{\pi }{2}-(-Cos\frac{\pi }{3})=0+\frac{1}{2}=\frac{1}{2}$

$2)log_{2}16=log_{2}2^{4}=4log_{2} 2=4$

$3)a(3;3;-3)\\\\|a|=\sqrt{3^{2}+3^{2}+(-3)^{2}}=\sqrt{9+9+9}=\sqrt{27}=3\sqrt{3}$

$4)V=\frac{4}{3} \pi R^{3}=\frac{4}{3}\pi*6^{3}=288\pi sm^{3}$