Question

Даны векторы а (3;-2;4), b (3;-2;4), c (6;5;1). Вычислите ab,ac,bc,aa

Answer 1

ab = 3*3 + (-2)*(-2) + 4*4 = 9 + 4 + 16 = 29

ac = 3*6 + (-2)*5 + 4*1 = 18 - 10 + 4 = 12

bc = 3*6 + (-2)*5 + 4*1 = 18 - 10 + 4 = 12

aa = 3*3 + (-2)*(-2) + 4*4 = 9 + 4 + 16 = 29