Question

Помогите решить 3-4 задания

Answer 1

$6=\sqrt{36}\\\\7=\sqrt{49}\\\\\sqrt{36}<\sqrt{42}<\sqrt{49}\\\\6<\sqrt{42}<7$

$\frac{25^{7} }{125^{5}}=\frac{(5^{2})^{7}}{(5^{3})^{5}} =\frac{5^{14}}{5^{15}}=\frac{1}{5}=0,2$