Question

найти значение выражения ((1-3i)/(2*5i))^2

Answer 1

$(\frac{1-3i}{2\cdot5i})^2 = (\frac{1-3i}{10i})^2 = \frac{1-6i+9i^2}{10^2\cdot i^2} = \frac{1-6i-9}{-100} = \frac{-8}{-100} + \frac{6}{100}i = \frac{4}{50} + \frac{3}{50}i$