Question

х-3:4х2+2•(6х+1:х-3+6х-1:х+3)

Answer 1

$\frac{x-3}{4x^2}+2(\frac{6x+1}{x-3}+\frac{6x-1}{x+3})= \frac{x-3}{4x^2}+2(\frac{6x^2+18x+x+3+6x^2-18x-x+3}{x^2-9})= \frac{x-3}{4x^2}+2(\frac{12x^2+6}{x^2-9})=\frac{x^3-9x-3x^2+27+96x^4+48x^2}{4x^2(x^2-9)}=\frac{96x^4+x^3+45x^2-9x+27}{4x^2(x^2-9)}$