Question

Срочно решение!!!!!!!!!!

Answer 1

$\frac{1}{2}log_{4}7+log_{4} 32-\frac{1}{2}log_{4}28=log_{4}\sqrt{7}+log_{4}32-log_{4}\sqrt{28}=log_{4}(\frac{\sqrt{7}*32 }{\sqrt{4*7} })=log_{4}(\frac{\sqrt{7}*32 }{2\sqrt{7}})=log_{4}16=2$