Question

2.2. Розв'яжіть систему рівнянь:
сразу відповідь можна

Answer 1

$\left \{ {{4x-y=3} \atop {2x^{2}+y^{2}=3}} \right.\\\\\left \{ {{y=4x-3} \atop {2x^{2}+(4x-3)^{2} =3}} \right.\\\\\left \{ {{y=4x-3} \atop {2x^{2}+16x^{2}-24x+9-3=0}} \right. \\\\\left \{ {{y=4x-3} \atop {18x^{2}-24x+6=0 }} \right.\\\\\left \{ {{y=4x-3} \atop {3x^{2}-4x+1=0}} \right.$

$3x^{2}-4x+1=0\\\\D=(-4)^{2}-4*3*1=16-12=4=2^{2}\\\\x_{1}=\frac{4-2}{6}=\frac{1}{3}\\\\x_{2}=\frac{4+2}{6}=1\\\\y_{1}=4*\frac{1}{3}-3=1\frac{1}{3}-3=-1\frac{2}{3} \\\\y_{2}=4*1-3=1\\\\Otvet:(\frac{1}{3};-1\frac{2}{3}),(1;1)$