Question

упростите выражение
$\frac{ \sqrt{3} }{ \sqrt{3 } - \sqrt{2} } - \frac{ \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$
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Answer 1

Ответ:

$...=\frac{\sqrt{3}*(\sqrt{3}+\sqrt{2})-\sqrt{2}*(\sqrt{3}-\sqrt{2}) }{(\sqrt{3}-\sqrt{2})*(\sqrt{3}+\sqrt{2}) }=\frac{(\sqrt{3})^2+\sqrt{3}*\sqrt{2}-\sqrt{2}*\sqrt{3}+(\sqrt{2})^2 }{(\sqrt{3})^2-(\sqrt{2})^2}=\frac{3+2}{3-2}=5$

Объяснение:

Answer 2

$\frac{\sqrt{3}}{\sqrt{3}-\sqrt{2}}-\frac{\sqrt{2}}{\sqrt{3}+\sqrt{2}} =\frac{\sqrt{3}*(\sqrt{3}+\sqrt{2})-\sqrt{2}*(\sqrt{3}-\sqrt{2})}{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})}=\frac{3+\sqrt{6}-\sqrt{6}+2}{(\sqrt{3})^{2}-(\sqrt{2})^{2}}=\frac{5}{3-2}=5$