Question

Пожалуйста помогите ))

Answer 1

3) ₋₂²∫хdx = x²/2|₋₂²= 4/2 - 4/2 = 0

6)₀¹∫(х² +1)dx = (x³/3 + x)|₀¹ = 1/3 +1 -0 = 4/3

2)₀³∫5dx = 5x|₀³ = 5*3-0 = 15

4)₀¹∫x²dx= x³/3|₀¹ = 1/3 - 0 = 1/3

14) ₂⁸∫dx/√х = 2√х|₂⁸ = 2√8 - 2√2 = 4√2 - 2√2 = 2√2

23)₀π∫(Sinx - 3Cosx -x)dx =( -Cosx -3Sinx - x²/2)|₀π =

= 1-0 -π²/2 - (-1 -0 -π²/2) = 1 -π²/2 +1 +π²/2 = 2

₀π∫Sinxdx = -Cosx|₀π = 1 -1 = 0

б) ₋₅¹∫(х² +8х +16)dx = (x³/3 +8x²/2 + 16x)|₋₅¹ = 1/3 +4 +16 - (-125/3 +4*25 -80)=

= 1/3 +4 +16 +125/3 - 100 + 80= 126/3