Question

памагите решить задание

Answer 1

1.

$\sqrt{8} = \sqrt{2 \times 4} = 2 \sqrt{2}$

$\sqrt{12} = \sqrt{3 \times 4} = 2 \sqrt{3}$

$\sqrt{48} = \sqrt{16 \times 3} = 4 \sqrt{3}$

$\sqrt{200} = \sqrt{25 \times 4 \times 2} = 5 \times 2 \times \sqrt{2} = 10 \sqrt{2}$

2.

$\sqrt{50 } - \sqrt{18} + \sqrt{72} = \sqrt{25 \times 2} - \sqrt{9 \times 2} + \sqrt{36 \times 2} = 5 \sqrt{2} - 3 \sqrt{2} + 6 \sqrt{2} = 8 \sqrt{2}$

3.

$5 \sqrt{3} < 4 \sqrt{5} \\ 5 \sqrt{3} = \sqrt{ {5}^{2} \times 3 } = \sqrt{25 \times 3} = \sqrt{75} \\ 4 \sqrt{5} = \sqrt{ {4}^{2} \times 5 } = \sqrt{16 \times 5} = \sqrt{80} \\ \sqrt{75} < \sqrt{80}$

Answer 2

Ответ:

Объяснение:

1)

√8= 2√2

√12= 2√3

√48= 4√3

√200= 10√2

2) 5√2-3√2+6√2= 8√2

0,3*4√2+1/3*3√2=1,2√2+√2= 2,2√2

3) √75 и √80

75<80

значит 5√3<4√5