Question

Помогите решить4
x^2+4x-45=0

Answer 1

Решение:

${x}^{2} + 4x - 45 = 0$

$d = {b}^{2} - 4ac$

$a = 1$

$b = 4$

$c = - 45$

$d = {4}^{2} - 4 \times 1 \times ( - 45) = 196$

$d > 0 = > 2 \: kornya$

$x1 = \frac{ - b + \sqrt{d} }{2a}$

$x2 = \frac{ - b - \sqrt{d} }{2a}$

$x1 = \frac{ - 4 + \sqrt{196} }{2}$

$x2 = \frac{ - 4 - \sqrt{196} }{2}$

$x1 = 5$

$x2 = - 9$

Ответ:

$x1 = 5$

$x2 = - 9$