Question

2 х^2 - 5 x - 7 ≥ 0       

х  ≥  3

Answer 1

$2x^2-5x-7 geq 0\ (x+1)(2x-7) geq 0\ left { {{2x-7 geq 0} atop {x geq 3}} right. \ x geq 3.5$
Ответ  [3.5;+oo)