Question

ПОМОГИТЕ, ПОЖАЛУЙСТА!!!
tg(2x-n/6)=1​

Answer 1

$tg(2x-\frac{\pi }{6})=1\\\\2x-\frac{\pi }{6}=arctg1+\pi n,n\in z\\\\2x-\frac{\pi }{6}=\frac{\pi }{4}+\pi n,n\in z\\\\2x=\frac{\pi }{4}+\frac{\pi }{6}+\pi n,n\in z\\\\2x=\frac{5\pi }{12}+\pi n,n\in z\\\\x=\frac{5\pi }{24}+\frac{\pi n }{2},n\in z$