Question

решить систему: x^2-y^2=8 x+y=4

Answer 1

x^2-y^2 = 8
x+y = 4

x=4-y
(4-y)^2-y^2=8  *

* 16 - 8y +y^2-y^2 = 8
-8y = -8
y=1

y=1
x=3