Question

4x2+4x-3=0, скажите пожалуйста​

Answer 1

$4 {x}^{2} + 4x - 3 = 0 \\ d = {4}^{2} - 4 \times 4 \times ( - 3) = 16 + 48 = 64 = {8}^{2} \\ x_{1} = \frac{ - 4 - 8}{2 \times 4} = - 1.5 \\ x_{2} = \frac{ - 4 + 8}{2 \times 4} = 0.5$

Answer 2

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