Question

(8x-3) (2x+1)=(4x-1)в2​

Answer 1

$(8x - 3)(2x + 1) = (4x - 1) {}^{2} \\ 16x {}^{2} + 8x - 6x - 3 = 16x {}^{2} - 8x + 1 \\ 10x = 4 \\ x = 4 \div 10 \\ x = 0.4$