Question

Помогите!___________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

Answer 1

$\frac{3^{6}*9^{-7}}{27^{-3} }=\frac{3^{6}*(3^{2})^{-7}}{(3^{3})^{-3}}=\frac{3^{6}*3^{-14}}{3^{-9}}=3^{6+(-14)-(-9)}=3^{6-14+9}=3$