Question

{6y-5x-1=0 {(x-1)/3+(y+1)/2=10 решите систему уравнения

Answer 1

6у-5х-1=0

(х-1)/3+(у+1)/2=10

 

6у-5х-1=0

6(х-1)/3+6(у+1)/2=10, 2(х-1)+3(у+1)=60, 2х-2+3у+3=60, 3у+2х=59, 6у+4х=118

 

6у-5х=1

6у+4х=118

 

9х=117

х=13

 

6у-13*5=1

6у-65=1

6у=66

у=11