Question

$left { {{3y-x=7} atop {y^{2} +3x=1}} right.$

Answer 1

$3y-x=7\ y^2+3x=1\ \ x=3y-7\ y^2+3(3y-7)=1\ y^2+9y-21=1\ y^2+9y-22=0\ D=81+4*1*22=13^2\ y_{1}=frac{-9+13}{2}=2\ y_{2}=frac{-9-13}{2}=-11\ x_{1}=-1\ x_{2}=-40$

Answer 2

Спасибо :3