Question

Помогите, надо найти a​

Answer 1

$\frac{ {9}^{ \frac{1}{3} } \times {3}^{ \frac{7}{3} } }{ {27}^{5} \times {9}^{ \frac{a}{3} } } = 3 \sqrt[3]{3} \\ \frac{ {3}^{ \frac{2}{3} + \frac{7}{3} }}{ {3}^{15 + \frac{2a}{3} } } = {3}^{ \frac{4}{3} } \\ {3}^{\frac{2a}{3} - 12} = {3}^{ \frac{4}{3} } \\ \frac{2a}{3} - 12 = \frac{4}{3} \\ 2a - 4 = 36 \\ a = 20$