Question

(x-5)^6+(x2-6x+7)^3=0

Answer 1

${(x - 5)}^{6} + {( {x}^{2} - 6x + 7) }^{3} = 0 \\ {(x - 5)}^{6} = - {( {x}^{2} - 6x + 7) }^{3} \\ {(x - 5)}^{2} = -{x}^{2} +6x - 7 \\ {x}^{2} - 10x + 25 = -{x}^{2} +6x -7 \\ 2{x}^{2}-16x+32=0\\{x}^{2}-8x+16=0\\{(x-4)}^{2}=0\\</p><p>x=4$