Question

СРОЧНО РЕШИТЕ 1 ВАРИАНТ!

Answer 1

$y=x^2-2x+1=(x-1)^2\; \; ,\; \; y=1+x\\\\Tochki\; peresecheniya:\; \; x^2-2x+1=1+x\; ,\; \; x^2-3x=0\; ,\\\\x(x-3)=0\; \; \to \; \; x_1=0\; \; ,\; \; x_2=3\\\\S=\int \limits _0^3\Big ((1+x)-(x^2-2x+1)\Big )\, dx=\int \limits _0^3(-x^2+3x)\, dx=\\\\=\Big (-\frac{x^3}{3}+3\cdot \frac{x^2}{2}\Big )\Big |_0^3=-9+\frac{27}{2}=\frac{9}{2}=4,5\; .$