Question

переведите в C++.

var n,k,n2:int64;

begin

read(n);

k:=0;

n2:=1;

while n2<=n do

begin

n2:=n2*2;

k:=k+1;

end;

write(k);

end.

Answer 1

#include <iostream>

#include <cmath>

int main()

{

int n;

std::cin>>n;

std::cout<<ceil(log(n)/log(2));

return 0;

}