Question

Решить систему управлений.
{х+2у=1/12
{2х-у=-1/4​

Answer 1

$\begin{cases}x+2y=\frac1{12}\\2x-y=-\frac14\end{cases}\Rightarrow\begin{cases}x=\frac1{12}-2y\\2\cdot\left(\frac1{12}-2y\right)-y=-\frac14\end{cases}\\\\2\cdot\left(\frac1{12}-2y\right)-y=-\frac14\\\frac16-4y-y=-\frac14\\5y=\frac16+\frac14\\5y=\frac5{12}\\y=\frac1{12}\\\\\begin{cases}x=-\frac1{12}\\y=\frac1{12}\end{caseS}$

Answer 2

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