Question

Решите пожалуйста даю 75 баллов

Answer 1

1)

$5 - 2x = 3(10 + x) \\ 5 - 2x - 30 - 3x = 0 \\ - 25 - 5x = 0 \\ - 5x = 25 \\ x = - 5$

2)

$\sqrt{x + 3} (5x - 6) = 0 \\ \sqrt{x + 3} = 0 \\ 5x - 6 = 0 \\ x + 3 = 0 \\ 5x = 6 \\ x = - 3 \\ x = \frac{6}{5} \\ - 3 + \frac{6}{5} = - 1.8$

3)

$3 {x}^{2} - 13x + 12 = 0 \\ d = 169 - 4 \times 3 \times 12 = 169 - 144 = 25 \\ x = \frac{13 + 5}{6} = 3 \\ x2 = \frac{4}{3} \\ \frac{4}{3} \times 3 = 4$

4)

$3(x - 2) - 2 > 4 - x \\ 3x - 6 - 4 + x > 0 \\ 4x - 10 > 0 \\ x > \frac{10}{4}$

5)

$2x - 5 < 0 \\ 7x + 28 > 0 \\ x < \frac{5}{2} \\ x > - 4$

Ответ 2

6)

${x}^{2} + 3x - 10 \leqslant 0 \\ x {}^{2} + 3x - 10 = 0 \\ x1 = - 5 \\ x2 = 2$

Ответ [-5;2]

Ответ 8