Question

Решите неравенство
$16 {x}^{2} - 1 > 0$
${x}^{2} + 5.1x < 0$

$3 {x}^{2} - 11x + 6 < 0$
$- {x}^{2} - 4x - 4 \leqslant 0$
$\frac{x }{x} \frac{ + }{ - } \frac{10}{11} \geqslant 0$
$(x - 5)(x + 1) < 0$
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Answer 1

Ответ:

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