Question

Будь ласка дуже терміново 16 і 21!!

Answer 1

16) y = - x² + 5x + 5

Если x = 2 , то  y = - 2² + 5 * 2 + 5 = - 4 + 10 + 5 = 11

x + y = 2 + 11 = 13

$21)\left \{ {{2x^{2}+5x-3\geq0} \atop {2-x\geq0 }} \right.\\\\\left \{ {{2(x+3)(x-0,5)\geq0 } \atop {-x\geq -2}} \right.\\\\\left \{ {{(x+3)(x-0,5)\geq0 } \atop {x\leq2 }} \right.$

           +                               -                             +

____________[- 3]___________[0,5]_____________

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________________________________________[2]_____

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Ответ : x ∈ (- ∞ ; - 3] ∪ [0,5 ; 2]

Answer 2

Розв'язання завдання додаю