Question

Знайдіть похідну функції => y=-x^8+7x^6+4/x-1

Answer 1

$1)y=-x^{8}+7x^{6}+\frac{4}{x}-1 \\\\y'=(-x^{8})'+7(x^{6})'+4(\frac{1}{x})'-1'=-8x^{7}+42x^{5}-\frac{4}{x^{2} }$

$2)y=-\frac{1}{6}x^{3}+0,5x^{2}+2x\\\\y'=-\frac{1}{6}(x^{3})'+0,5(x^{2})'+2(x)'=-\frac{1}{6}*3x^{2}+0,5*2x+2=-\frac{1}{2}x^{2}+x+2$