Question

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Answer 1

$\frac{4x^{2}-7x-2 }{11x-4x^{2}+3 }=-\frac{4x^{2}-7x-2 }{4x^{2}-11x-3 }=-\frac{4(x-2)(x+\frac{1}{4}) }{4(x-3)(x+\frac{1}{4}) }=-\frac{x-2}{x-3}=\frac{x-2}{3-x}$