Question

помогите, алгебра!!!​

Answer 1

$y=5x-2\\\\f(3)=5\cdot 3-2=15-2=13\\\\f(0)=5\cdot 0-2=-2\\\\f(-2,1)=5\cdot (-2,1)-2=-10,5-2=-12,5\\\\f(2\frac{3}{5})=f(\frac{13}{5})=5\cdot \frac{13}{5}-2=13-2=11\\\\f(-4)=5\cdot (-4)-2=-20-4=-24$