Question

help me pls, dude. TY

Answer 1

$\frac{2^{2k+1}*3^{2k-2}}{8*6^{2k-2} }=\frac{2^{2k+1}*3^{2k-2}}{2^{3}*(2*3)^{2k-2}}=\frac{2^{2k+1}*3^{2k-2}}{2^{3}*2^{2k-2}*3^{2k-2}}=2^{2k+1-3-2k+2}=2^{o}=1$