Question

⚠️⚠️НУЖНА ПОМОЩЬ ⚠️⚠️​

Answer 1

$x^2+px+q=0\; \; \Rightarrow\; \; \left \{ {{p=-(x_1+x_2)} \atop {q=x_1\cdot x_2\quad \; \; }} \right. \\\\x_1=-\frac{1}{5}\; \; ,\; \; x_2=2\\\\p=-(-\frac{1}{5}+2)=-\frac{9}{5}\\\\q=-\frac{1}{5}\cdot 2=-\frac{2}{5}\\\\x^2-\frac{9}{5}\, x-\frac{2}{5}=0\; |\cdot 5\\\\\underline {5x^2-9x-2=0}$