Question

{3(x+2y)-y-27=0
{4(x+y)-3x-23=0
​решите системы уравнений методом подстановки

Answer 1

3(x + 2y) - y - 27 = 0

4(x + y) - 3x - 23 = 0

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3x + 6y - y = 27

4x + 4y - 3x = 23

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3x + 5y = 27

x + 4y = 23

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3x + 5y = 27

x = 23 - 4y

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69 - 12y + 5y = 27

x = 23 - 4y

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-7y = -42

x = 23 - 4y

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y = 6

x = -1

Ответ: y = 6, x = -1