Question

Добрый вечер! Помогите решить :)

Answer 1

$\displaystyle\mathbf{\int{\sqrt{x}+\sqrt[3]{x^4}\over x}\mathrm{dx}=\int(x^{-{1\over2}}+x^{1\over3})\mathrm{dx}={x^{-{1\over2}+1}\over -{1\over2}+1}+{x^{{1\over3}+1}\over {1\over3}+1}+C=2\sqrt{x}+{3\over4}\sqrt[3]{x^4}+C}$