Question

(3 1/7-n)+1 4/7=35/7+2/7​

Answer 1

$(3\frac{1}{7}-n)+1\frac{4}{7}=3\frac{5}{7}+\frac{2}{7}\\\\(\frac{22}{7}-n)+\frac{11}{7}=\frac{26}{7}+\frac{2}{7}\\\\\frac{33}{7}-n=\frac{28}{7}\\\\n=\frac{33}{7}-\frac{28}{7}\\\\n=\frac{5}{7}$

Answer 2

Дано:

$(3 \frac{1}{7} - n) + 1 \frac{4}{7} = \frac{35}{7} + \frac{2}{7}$

Задание: Найти N (Решить уравнение)

Решение:

$(3 \frac{1}{7} - n) + 1 \frac{4}{7} = \frac{35}{7} + \frac{2}{7} \\ 3 \frac{1}{7} - n = 5 \frac{2}{7} - 1 \frac{4}{7} \\ 3 \frac{1}{7} - n = 3 \frac{5}{7} \\ - n = \frac{4}{7} \\ n = - \frac{4}{7}$

Ответ:

-4/7

Проверка:

$(3 \frac{1}{7} + \frac{4}{7} ) + 1 \frac{4}{7} = \frac{35}{7} + \frac{2}{7} \\ 3 \frac{5}{7} + 1 \frac{4}{7} = 5 \frac{2}{7} \\ 5 \frac{2}{7} = 5 \frac{2}{7}$