Question

Задание приложено ниже.

Answer 1

$1)2arctg1+3arcsin(-\frac{1}{2} )=2*\frac{\pi}{4} +3*(-\frac{\pi}{6} )=\frac{\pi}{2} -\frac{\pi}{2}=0\\\\2)arctg\sqrt{3} =\frac{\pi}{3} \\arccos\frac{1}{2} =\frac{\pi}{3} \\\\arctg\sqrt{3}=arccos\frac{1}{2} \\\\3)-arctg(5)<arctg(0)$