Question

.HELP.АЛГЕБРА 7 КЛАСС​

Answer 1

Ответ:

Объяснение:

1. t² - 36 ≠ 0 ; t² ≠ 36 ; t ≠ ±6

2. $\frac{7*4*a*a}{7*3*a} = \frac{4a}{3}$

3. $\frac{(2a-3b)^2}{2a-3b} = 2a-3b\\\\a=2, b=3, 2*2-3*3 = 4-9=-5$

4. a) $\frac{1}{2a} + \frac{1*2}{a*2} = \frac{3}{2a}$

b) $\frac{3}{3-y} - \frac{y}{(y-3)(y+3)} = \frac{3}{3-y} + \frac{y}{(3-y)(y+3)} = \frac{3*(y+3)}{(3-y)*(y+3)} + \frac{y}{(3-y)(y+3)} = \frac{4y+9}{(3-y)(y+3)}$

5. a) $\frac{5*x*2*7*y}{7*y*5*3*x} = \frac{2}{3}$

b) $\frac{a*(a-b)}{b*(a+b)} * \frac{6*(a+b)}{3*(a-b)} = \frac{6*a*(a+b)*(a-b)}{3*b*(a+b)*(a-b)} = \frac{2a}{b}$