Question

надо решить систему уравнений​

Answer 1

$x = 6 + {y}^{2} \\ x {y}^{2} = 7$

$(6 + {y}^{2} ) \times {y}^{2} = 7$

$y = - 1 \\ y = 1$

$x = 6 + ( - 1) ^{2}$

$x = 6 + 1 ^{2}$

Ответ: (х1;у1)=(7;-1)

(х2;у2)=(7;1)

Answer 2

х=6+у^2

(6+у^2)×у^2=7

6у^2+у^4=7

у^4+6у^2-7=0

у^4=t

t^2+6t-7=0

D=36-4×(-7)=36+28=64

t1=-6-8/2=-14/2=-7

t2=-6+8/2=2/2=1