Question

sin^2x+2sinx*cosx=0​

Answer 1

Ответ:

$\sin(2x) + 2 \sin(x) \times \cos(x) = 0 \\ \sin(2x) + \sin(2x) = 0 \\ 2 \sin(2x) = 0 \\ \sin(2x) = 0 \\ 2x = k\pi \\ x = \frac{k\pi}{2}$